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What is the length of AD in the parallelogram below?
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well we know its not 4 or 6 because its longer than the (6) imaginary line
if it were me id go with 10 because its a little bit smaller than (12) imaginary and bigger than (6)
IMA GO WITH 10
i believe it is 8 because you have to subtract 12 from 16 which is 4 then you do A.squared + B.squared=C. squared C=AD so do 4 squared + 6 squared =56 and the square root of 56 is 7.21 and there is enough variation there to be equal to 8
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