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Mathematics 21 Online
OpenStudy (anonymous):

The current size of an image on Samuel's computer is shown below: A rectangle is shown. The length of the rectangle is labeled as length equal to 8 inches and the width is labeled as width equal to 10 inches. What are the dimensions of the image at fraction 1 over 2 times its current size? Length = 4 inches, width = 5 inches Length = 6 inches, width = 8 inches Length = 10 inches, width = 12 inches Length = 16 inches, width = 20 inches

OpenStudy (anonymous):

OpenStudy (anonymous):

@MARC_ @rational @dan815

OpenStudy (anonymous):

@BriellShaw

OpenStudy (briellshaw):

the correct answer is a 10/2 8/2 = 4w 5l

OpenStudy (anonymous):

im confused which one is tht

OpenStudy (briellshaw):

A

OpenStudy (anonymous):

thxx

OpenStudy (briellshaw):

Your Welcome!!!

OpenStudy (anonymous):

will u help me with one more

OpenStudy (briellshaw):

Sure

OpenStudy (anonymous):

The area of a triangle is 24 square inches. What is the height of the triangle if the base length is 8 inches? 6 inches 8 inches 12 inches 16 inches

OpenStudy (briellshaw):

16 24-8=16

OpenStudy (anonymous):

thank u :)

OpenStudy (briellshaw):

YW

OpenStudy (briellshaw):

Just remember to close your question

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