Question

Below is a graph that represents the total profits for a third month. Write the equation of the line that represents this graph. Show your work or explain how you determined the equations.

Answer 1

http://learn.flvs.net/webdav/educator_algebraI_v17/module03/images/03_03_assessment/03_03_assessment.gif

Answer 2

Tell me if you're not able to see the picture.

Answer 3

@Ashes.boom ( sorry for asking you so much q's)

Answer 4

its okay :)

Answer 5

couldn't see the pic

Answer 6

i couldnt se it either

Answer 7

there you go

Answer 8

c:

Answer 9

okay start with y intercept. What point is the y intercept?

Answer 10

3

Answer 11

oh waiton the graph? xD

Answer 12

technically 300 yes

Answer 13

haha yea

Answer 14

so they y intercept is 300?

Answer 15

yes

Answer 16

so now you have y = mx + 300

Answer 17

remmebr how to find the slope

Answer 18

the slope is 150?

Answer 19

slope is a fraction becuase the formula is y2 - y1 / x2 - x1
so use the y intercept as one point and find another point to use for the second one

Answer 20

hmm??

Answer 21

actually its x2-x1 / y2 - y1 , am i right ?

Answer 22

the y goes first i think

Answer 23

okay so the y intercept is at point 0, 300

Answer 24

the other point i see is 150, 200

Answer 25

200-300 over 150 - 0

Answer 26

100/150

Answer 27

100/150 = 10/15 = 2/3

Answer 28

the line is going down so its subtraction

-2/3

Answer 29

y = -2/3x + 300

Answer 30

man i really dislike math. Thank you so much for helping me with my assignment, i would follow you ashes but idk how bc open study changed stuff and it's not like popping your name up when i hoover my mouse over it.

Answer 31

sorry my internet went out!