Question

I will give medal\

A history class is comprised of
10
female and
5
male students. If the instructor of the class randomly chooses
8
students from the class for an oral exam, what is the probability that
5
female students and
3
male students will be selected? Round your answer to
3
decimal places.

Answer 1

Sure Sweetie

Answer 2

Use the hypergeometric distribution. In all, there are (14 choose 6) ways of choosing 6 students from the class. Of these, there are (6 choose 2)·(8 choose 4) ways of choosing 2 girls and 4 boys. So the desired probability is
((6 choose 2)·(8 choose 4))/(14 choose 6)
((6!/(4!2!))·(8!/(4!4!))) / (14!/(6!8!))
= (5·10)/(11·13) = 50/143 = 0.3497.

Answer 3

Did this Help? :)

Answer 4

Yes