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a person walks 25 degrees south of west for 2 km. how far would he walk due to south? due to west?
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|dw:1429202929260:dw| \[\color{green}{\vec{d}_y = \vec{d} \cdot \cos 65^\circ\\ \vec{d}_x = \vec{d} \cdot \sin 65^\circ}\] The directions will be as shown in the diagram. Use 2 km for vector d when you solve the equations shown above.
wont that b -d
@ghuczek
-d.sin65
Yes, if you assign negative values for down and left. Exactly.
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can u help me out in 1 more
vector B has the magnitude of 20 cm and is directed 25 anti clockwise. from - xaxis express in unit vctr notation
|dw:1429282402749:dw|\[\color{green}{\vec{B}_x = - \vec{B} \cdot \cos 25^\circ\\ \vec{B}_y =- \vec{B} \cdot \sin 25^\circ}\]
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