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Odd numbers .
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If \(P\) ,\(Q\) and \(R\) are three consecutive odd numbers in ascending order .If the values of 3 times \(P\) is three less than two times \(R\) , Find the value of \(R\). \(\large \color{black}{\begin{align} a.)\quad 5\hspace{.33em}\\~\\ b.)\quad 7\hspace{.33em}\\~\\ c.)\quad 9\hspace{.33em}\\~\\ d.)\quad 11\hspace{.33em}\\~\\ \end{align}}\) \(\large \color{black}{\begin{align}&P=2n-1,Q=2n+1,R=2n+3\hspace{.33em}\\~\\ &3P-3=2R\hspace{.33em}\\~\\ &3(2n-1)-3=2(2n+3)\hspace{.33em}\\~\\ &n=6 \hspace{.33em}\\~\\ &R=2n+3=15 \end{align}}\)
3P = 2R - 3 the value of 3P is, 3 less then 2R
it doesnt read: the value of 3P less 3, is equal to 2R
oh ok that was helpful thnks
yep
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