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Mathematics 14 Online
OpenStudy (anonymous):

URGENT MEDALS GIVEN PLEASE HELP

OpenStudy (anonymous):

prove:tan2θ×cos2θ+cos2θ=1

OpenStudy (melissa_something):

Hold on. Is this multiple choice?

OpenStudy (anonymous):

no i just have to work it out to prove it but i d k how

OpenStudy (anonymous):

@Melissa_Something

OpenStudy (melissa_something):

Simplify the left side first. Sin(20) + cos (20) = 1 because they are ratio identities

OpenStudy (melissa_something):

Add 0.34202014 and 0.93969262 to get 1.28171276

OpenStudy (melissa_something):

Since the left side dosent equal 1 this is false

OpenStudy (anonymous):

are you sure because i ran it through wolfram alpha to see if it was true or false before i tried to figure it out and it came up equal to one

OpenStudy (anonymous):

oh wait it looks wrong on here

OpenStudy (melissa_something):

No, this is really easy, you just plug it into the calculator ? o.o

OpenStudy (anonymous):

\[prove: \tan ^{2}\theta \times \cos ^{2}\theta + \cos ^{2}\theta=1\]

OpenStudy (anonymous):

@Melissa_Something this is what it is supposed to look like. Its trigonometry

OpenStudy (melissa_something):

Oh then yes 1=1 when simplified!

OpenStudy (anonymous):

but i cant figure out how to get the problem to equal 1? @Melissa_Something

OpenStudy (melissa_something):

Ok. Tan^2 (0) will equal 0. Cos(0) =1. One to any power is 1. Mult. 1 by 0 to get 0. Again, Cos(0) is 1 so 0+1^2 and 1 to any power is 1. and 0+1 =1

OpenStudy (melissa_something):

1=1 :) It's so easy to do on the calculator

OpenStudy (anonymous):

I get it now!!!! THANKS!

OpenStudy (melissa_something):

np :)

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