Question

f(x)=2x^2-2x-3

Answer 1

I have to find the coordinate of the min point. I got 1/2 already.

Answer 2

that is the where the x value of it is, now you need to find the y value there as well, so x=1/2 plug that into the equation

Answer 3

you can see that 1/2 is right by using the formula
minX=-b/2a where b is the coefficient on the X term and a is the coefficient on x^2 term
minX=-(-2)/2*2 = 2/4=1/2

Answer 4

now find the value there
f(x) = 2x^2-2x-3
f(1/2)=2(1/2)^2-2(1/2)-3
=???

Answer 5

I got 3! @dan815 thank you

Answer 6

But the answer says min; (1/2 and -7/2)

Answer 7

Idk where 7/2 comes from :(

Answer 8

yes, check your math

Answer 9

oh -2 sorry

Answer 10

f(1/2)=2(1/2)^2-2(1/2)-3
=2*(1/4)-2/2-3
=1/2 -1-3
=-7/2

Answer 11

Does this clear it up?

Answer 12

Yes I reviewed your work and I got it -.- Thanks lol

Answer 13

okay byee :)