Question

QUick trig check...half angle tan 112.5 degrees

Answer 1

I got -1/sqrt 2

Answer 2

correct?

Answer 3

sin(a)/1+cos(a)

\[\frac{ \frac{ -1 }{ \sqrt{2} } }{ 1+\frac{ 1 }{ \sqrt{2} } }\]

Answer 4

multiplied the 1 by sqrt2/sqrt2

Answer 5

added it up, crossed out the sqrt of 2

Answer 6

got -1/sqrt2 over 1

Answer 7

@TheSmartOne

Answer 8

@freckles @ksanka

Answer 9

@Nnesha @perl

Answer 10

\[\tan(\frac{ B }{ 2})=\frac{ sinB }{ 1+cosB }\]

Answer 11

\[\frac{ -\frac{ 1 }{ \sqrt{2} } }{1-\frac{ 1 }{ \sqrt{2} } }\]

Answer 12

\[\frac{ -1 }{ \sqrt{2}-1 }\]

Answer 13

thats it?

Answer 14

yeah that is exac t answer

Answer 15

is that clear or do you need something explained?

Answer 16

is my friend also right? also, how can i check my answer is correct using a calculator?

Answer 17

do tan112.5 on a calculator and match it to your answer

Answer 18

im not getting the same answer

Answer 19

yes your friend is correct

Answer 20

the answer you gave was wrong, I gave the right answer

Answer 21

no i mean checking on the calculator

Answer 22

tan(112.5) in degrees gives you -2.414

the answer I gave you gives you -1-sqrt(2) which is the same answer

Answer 23

oh yeah, i got it now. thanks again.

Answer 24

i should stop studying for 3 tests at once

Answer 25

i made a dumb mistake here

Answer 26

you weer on the right track just one small mistake

Answer 27

lol yeah, im gonna go work on this more letter. i'm gonna take one test at a time. thanks man

Answer 28

*later

Answer 29

take care and good luck