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Mathematics 9 Online
OpenStudy (anonymous):

(i) sinh(x+1)−sinh(x)=(􀀀1+cosh(1))sinh(x)+sinh(1)cosh(x) (ii) cosh(x+1)−cosh(x)=(􀀀1+cosh(1))cosh(x)+sinh(1)sinh(x) use simultaneous equation method to get coshx=(Acosh(x+1)+Bsinh(x+1))−(Acosh(x)+Bsinh(x)) ( please show complete calculations , I am a slow learner , thank you)

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