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What is the approximate volume of a cone with a height of 12 in. and radius of 9 in.? Use 3.14 to approximate pi, and rexpress your final answer to the nearest tenth.
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@johnweldon1993 or anyone
So the equation would be \[\large V = \frac{\pi r^2 h}{3}\] So plugging everything in we have \[\large V = \frac{3.14\times 9^2 \times 12}{3}\] What does that come out to equal?
35532.2
Not quite...so we have \[\large \frac{3.14 \times 81 \times 12}{3}\]
31283.82 @johnweldon1993
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1017.36
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