Question

Factor completely 3x3 - 3x2 - 18x.

3x(x + 3)(x + 2)
3x(x + 3)(x - 2)
3x(x - 3)(x + 2)
3x(x - 3)(x - 2)

Answer 1

ik its not a or d

Answer 2

Each equation has at least 1 'x' in it right?

so we can factor one of those out

\[\large x(3x^2 - 3x - 18)\]

We also know that each term is divisible by 3 so we can factor out a 3 as well

\[\large 3x(x^2 - x - 6)\]

Now we can just factor the inside...

what 2 numbers multiply to make -6 and also add to make -1?

Answer 3

-3 and 2

Answer 4

so its b

Answer 5

-3 and 2 so it's *C*

Answer 6

oh lol thx

Answer 7

think u could help with another @johnweldon1993