Question

Solve 81^x = 27^(x + 2)


x = 1
x = 2
x = 5
x = 6

Answer 1

\(\large \bf {
81^x = 27^{x+2}\qquad {\color{brown}{ 3^4=81\qquad 27=3^3}}\qquad (3^4)^x=(3^3)^{x+2}
\\ \quad \\
3^{4\cdot x}=3^{3\cdot (x+2)}
}\)