Question

The work of a student to solve the equation 2(5y – 2) = 12 + 6y is shown below:

Step 1: 2(5y – 2) = 12 + 6y

Step 2: 7y – 4 = 12 + 6y

Step 3: y – 4 = 10

Step 4: y = 14

Step 5: y = 7

In which step did the student first make an error and what is the correct step?


Step 2: 7y – 4 = 6 + 3y
Step 2: 10y – 4 = 12 + 6y
Step 3: 5y – 2 = 2(10 + 3y)
Step 3: 2(5y – 2) = 10 + 3y

Answer 1

hlp

Answer 2

when you distribute you dont add you multiply

Answer 3

soooo?

Answer 4

check how to distribute. taught you this before

Answer 5

yes distribute first

Answer 6

when distributing always multiply never add
this gives you a huge hint