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\[\log_{x-1} 16=4\]
@jdoe0001
\(\large { \log_{{\color{brown}{ x-1 }} } {\color{blue}{ 16}}=4\implies {\color{blue}{ 16}}={\color{brown}{ (x-1)}}^4\qquad \begin{array}{llll} hint:\\ \textit{keep in mind that }16=2^4 \end{array} }\)
x=3 right?
hmm well... how did you get x =3 though?
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because (x-1)^4
Thanks :) Can you help me with one more?
hmmm that's a good way to do it, yes and then take the quartic root
you could post anew, thus if I dunno, someone else may know
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