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A 1,500 kg car coasts down a hill starting from rest and decreases its height by 22 m over a distance of 100 m of travel. How fast will it be going at the end of the hill, if friction has no effect in slowing its motion? 21 m/s *me answer* 15 m/s 44 m/s 800 m/s
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@kidrah69
idk know this one :/ @radar
@radar can you help me check this?
@amistre64 can you help me check this?
wheres your work or at least a thought process
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ok so : so (1/2)mv² = mgΔh v² = 2gΔh v = √[2 * 9.8 * 22] v = 21 m/s
going fancy on me are you ... good thought tho
is it right tho?
lets try a different approach, something more boring and triggy |dw:1429402830820:dw|
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