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is cos(2*pi*n) = 1?
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period of \(\cos(x)\) is \(2\pi\), therefore adding/subtracting an integer multiple of \(2\pi\) wont change the function's value : \[\cos(x) = \cos(x\pm2n\pi)\]
\[\cos(2n\pi) = \cos(0+2n\pi) = \cos(0) = 1\]
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