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\[\begin{align*} 0&=dz-(4x^3-4x^3z+x^3z^2)\,dx+(4y-1)(2-z)^2\,dy\\\\ &=dz-x^3(4-4z+z^2)\,dx+(4y-1)(2-z)^2\,dy\\\\ &=dz-x^3(2-z)^2\,dx+(4y-1)(2-z)^2\,dy\\\\ \frac{dz}{(2-z)^2}&=x^3\,dx+(1-4y)\,dy \end{align*}\]
Yes yes! You're too fast. Ill just integrate your final answer separately and thats it! Thank you so much @SithsAndGiggles =)
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