Question

Perform the indicated operation 4/7x^2-3/2x^3 I got 1/14x^2

Answer 1

4/49−3/2x^3

Answer 2

How?

Answer 3

use PEMDAS, Orders of Operations and Simplify

Answer 4

Well my options are\[A) \frac{ -8x+21 }{ 14x ^{3}}\]\[B) \frac{ 8x+21 }{ 14x ^{3} }\]\[C) \frac{ -8+21 }{ 14x ^{3} }\]\[D) \frac{ 8x-21 }{ 14x ^{3} }\]

Answer 5

@SolomonZelman

Answer 6

or anyone

Answer 7

@campbell_st

Answer 8

well you need a common denominator... so given 7x^2 and 2x^3 the common denominator will be 14x^3 so that's the main task of the question

\[\frac{4}{7x^2} \times \frac{2x}{2x} - \frac{3}{2x^3} \times \frac{7}{7} = \frac{8x}{14x^3} - \frac{21}{14x^3}\]

I'll let write it in a simpler form

hope it helps

Answer 9

Yes it does. Thank you