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Mathematics 16 Online
OpenStudy (anonymous):

Help me please!!

OpenStudy (anonymous):

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OpenStudy (anonymous):

answer in

OpenStudy (anonymous):

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OpenStudy (anonymous):

help please

geerky42 (geerky42):

\[\large \sqrt{m^{23}} = \sqrt{m^{22}\cdot m} = \sqrt{m^{22}}\sqrt m = \boxed{m^{11}\sqrt{m}}\]

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