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A ball is thrown vertically upward.After (t) seconds, its height (h) (in feet) is given by this function h(t)=96t-16t^2. What is the maximum height that the ball will reach? Check Answer for me please?
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I got the answer 144 ft. Is it correct?
Calculus or algebra ? (we can do either here)
College Algebra
Ok so I assumed you found the x-coordinate of the vertex and then plugged that into the function to find the max height?
yes
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can I ask what you got for the x-coordinate of the vertex?
3
awesome
let me check the rest one sec
\[h(3)=96(3)-16(3)^2=288-144=144\] you are right
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okay thankyou :)
you get a medal because you answered your own question
good job :)
awesome :)
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