Question

de

Answer 1

Cant deal with this dy/dx ^2

Answer 2

Take the square root of both sides first.

Answer 3

\[
|y'| = \frac{\sqrt{1-y^2}}{\sqrt{1-x^2}} \implies \int\frac{|y'|}{\sqrt{1-y^2}}dx = \int\frac{1}{\sqrt{1-x^2}}dx
\]