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How do you factor: 2sinΘcosΘ-sinΘ=0 ?
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My question derived from sin2Θ-sinΘ=0
Can someone show me how 2sinΘcosΘ-sinΘ is factored into sinΘ(2cosΘ-1)=0 ?
you can factor your thingy on the left hand side sin(x)(2 cos(x)-1)=0
oh lol
you have a question about that
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yes
do you see that both terms have the factor sin(x) in common?
I don't know how my text book got sinx(2cosx-1)=0
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