Mathematics
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OpenStudy (df001):
Help solving: Cos2Θ+2Cos²Θ=2 with angle formulas
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OpenStudy (df001):
I need help on factoring please
OpenStudy (df001):
but I dont know if I am suppose to bring the 2 to the other side before I factor
OpenStudy (anonymous):
What sign is that?
OpenStudy (anonymous):
What kind of math is that?
OpenStudy (anonymous):
Θ
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OpenStudy (anonymous):
Is that theta?
OpenStudy (anonymous):
I think so
OpenStudy (anonymous):
Theta = 1/6 (6 pi n-pi), n element Z
OpenStudy (anonymous):
this is calculus isn't it
OpenStudy (anonymous):
Theta = 1/6 (6 pi n+pi), n element Z
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OpenStudy (anonymous):
this is trigonometry
OpenStudy (anonymous):
haha trig is even worse for me lol
OpenStudy (df001):
Can the equation be rewritten as Cos2Θ+2Cos²Θ-2=0
OpenStudy (anonymous):
2 cos(2 Theta) = 1 alternate form
OpenStudy (anonymous):
2 cos(2 Theta)+1 = 2
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OpenStudy (anonymous):
-2 sin^2(Theta)+2 cos^2(Theta)+1 = 2
OpenStudy (anonymous):
alternate form
OpenStudy (df001):
wait before factoring, do I have to bring 2 to the left side of the equation?
OpenStudy (df001):
Cos2Θ+2Cos²Θ=2
OpenStudy (df001):
If I am correct, once the two is brought to the left and factored, it should be
Cos²Θ(1-sin²Θ+2-2)=0?
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OpenStudy (anonymous):
I used the graph
OpenStudy (df001):
I am trying to solve this algebraically lol :)
OpenStudy (triciaal):
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