Question

question with circuits.

Answer 1

My question is, when I apply KVL to loop 1, shouldn't it be 6V - 4(2) - 6(i) = 0. But if that was so, my current across 6 ohm resistor would be 1/3. But it's actually 2, because solving loop 2 gives the current across 6 ohm resistor as 2 amps. Why doesn't the first loop add up to 0?

Answer 2

when doing KVL, why doesnt it add up to zero?

Answer 3

anyone? pleeeease! :'(

Answer 4

show kvl loops work