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Mathematics 16 Online
OpenStudy (anonymous):

LIL HELP PLZZ MEDAL AND FAN

OpenStudy (anonymous):

OpenStudy (matthew1286):

im thinking 7 but not fully sure

OpenStudy (anonymous):

ok

OpenStudy (matthew1286):

wait for another person

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

since \[a^2+b^2=c^2\] and we know \[12^2+b^2=19^2\] We can rewrite this as \[19^2-12^2=b^2\] or 361-144=217 so we know b^2 = 217 so b = \[\sqrt{217}\]

OpenStudy (anonymous):

I'm thinking it might be Square root of 217.

OpenStudy (matthew1286):

im thinking so to

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