Can someone check my answer? I got C
\(\textit{function transformations} \\ \quad \\ \begin{array}{llll} \begin{array}{llll} shrink\ or\\ expand\\ by\ {\color{purple}{ A}}\end{array} \qquad \begin{array}{llll} vertical\\ shift\\ by \ {\color{green}{ D}} \end{array} \begin{array}{llll}{\color{green}{ D}} > 0& Upwards\\ {\color{green}{ D}} < 0 & Downwards\end{array} \\ % template start \qquad \downarrow\qquad\qquad\quad\ \downarrow\\ y = {\color{purple}{ A}} \sqrt{ x + {\color{red}{ C}} } + {\color{green}{ D}}\\ %template end \qquad\qquad \quad \uparrow \\ \qquad\begin{array}{llll} horizontal\\ shift\\ by \ {\color{red}{ C}}\end{array} \begin{array}{llll}{\color{red}{ C}} > 0 & to\ the\ left\\ {\color{red}{ C}} < 0& to\ the\ right\end{array} \end{array}\) so..... should be simple enough
ok well let me think
then it would shift either way
NVM i feel dumb
either way? well, is a transformation so, yes
It would be D left
is "C" > 0 or < 0? that is, is C positive or negative?
-15 = left = going negative
ahhh -15, that means C = -15 -15 is < 0 so C < 0, or C is negative, sooooo
if your going on a graph riight, then it would still be going left cause you have x before y
ehheh C = -15 or C < 0, or C is negative thus 15 units to the "right" is the transformation notice here -> http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiJzcXJ0KHgpIiwiY29sb3IiOiIjMDAwMDAwIn0seyJ0eXBlIjowLCJlcSI6InNxcnQoeC0xNSkiLCJjb2xvciI6IiNEOTE0MTQifSx7InR5cGUiOjEwMDAsIndpbmRvdyI6WyItNi4xNTI1MzkwNjI0OTk5OTciLCIzMy41MjAzMTI0OTk5OTk5OSIsIi0xMi4yNjcwMzEyNDk5OTk5OTciLCIxMi4xNDcwMzEyNDk5OTk5OTYiXX1d
oh so it would be opposite
yes, for the "x" or horizontal shift is a bit counterintuitive, yes you'd expect negative to go to the left but goes the other way that's true only for the horizontal shift :)
its weird though how'd it would go right.. I would of never of gotten A without your help!
thank you for the help
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