Question

Can someone check my answer! I got B

Answer 1

Question?

Answer 2

before you ask... click to zoom

Answer 3

\(\textit{function transformations}
\\ \quad \\

\begin{array}{llll}

\begin{array}{llll} shrink\ or\\ expand\\ by\ {\color{purple}{ A}}\end{array}
\qquad
\begin{array}{llll} vertical\\ shift\\ by \ {\color{green}{ D}} \end{array}

\begin{array}{llll}{\color{green}{ D}} > 0& Upwards\\ {\color{green}{ D}} < 0 & Downwards\end{array}
\\

% template start
\qquad \downarrow\qquad\qquad\quad\ \downarrow\\
y = {\color{purple}{ A}} \sqrt{ x + {\color{red}{ 4}} } + {\color{green}{ 3}}\\
%template end
\qquad\qquad \quad \uparrow \\

\qquad\begin{array}{llll} horizontal\\ shift\\ by \ {\color{red}{ C}}\end{array}

\begin{array}{llll}{\color{red}{ C}} > 0 & to\ the\ left\\ {\color{red}{ C}} < 0& to\ the\ right\end{array}
\end{array}\)

Answer 4

Not quite.
\(\Large y=\sqrt[3]{x-h}+k\)

h= horizontal translation
k = vertical translation

Answer 5

ok then D is correct guys?

Answer 6

h would mean -4 left

Answer 7

hehe are you even reading the transformations templates?

Answer 8

+3 would be up

Answer 9

No. Notice the question says "x-4"

Answer 10

yes +3 is up
and -4 is?

Answer 11

meaning h=4

Answer 12

yes I am looking at what you guys wrote but ... is this another opposite one

Answer 13

but h isnt positive

Answer 14

h is positive.

Answer 15

ohh wait a sec... thought it was -4 dohh ahemm

Answer 16

x - h
x - 4

thus, h = 4

Answer 17

well ok.. but thats a stupid math rule

Answer 18

anyhow \(\textit{function transformations}
\\ \quad \\

\begin{array}{llll}

\begin{array}{llll} shrink\ or\\ expand\\ by\ {\color{purple}{ A}}\end{array}
\qquad
\begin{array}{llll} vertical\\ shift\\ by \ {\color{green}{ D}} \end{array}

\begin{array}{llll}{\color{green}{ D}} > 0& Upwards\\ {\color{green}{ D}} < 0 & Downwards\end{array}
\\

% template start
\qquad \downarrow\qquad\qquad\quad\ \downarrow\\
y = {\color{purple}{ A}} \sqrt{ x - {\color{red}{ 4}} } + {\color{green}{ 3}}\\
%template end
\qquad\qquad \quad \uparrow \\

\qquad\begin{array}{llll} horizontal\\ shift\\ by \ {\color{red}{ C}}\end{array}

\begin{array}{llll}{\color{red}{ C}} > 0 & to\ the\ left\\ {\color{red}{ C}} < 0& to\ the\ right\end{array}
\end{array}\) there

Answer 19

Why do you say that? @Howard-Wolowitz

Answer 20

why does it have to be positive if its already negative?

Answer 21

I'm going with C

Answer 22

C is correct.

Answer 23

Thanks guys!

Answer 24

math rules are made by observation of phenomena patterns

so, is not like we tell nature to make "stupid" rules
is that nature makes them and we write them down in a notation or formula

now if you think they're "stupid" well, tell nature that :)

Answer 25

my problem is that I dont get why they switch values

Answer 26

Notice this:
x - h

You have x - 4

So...
x - h = x - 4
-h = -4
h = 4

So, the value of h was never negative.

Answer 27

I think I understand.. but you admit its dumb

Answer 28

hmm we've just covered that about 5mins ago in the previous one

how come is an issue? assuming you're really reading the templates :)

Answer 29

I don't think its dumb.

Answer 30

no i get it but this is my first time doing it

Answer 31

On the other hand, if it had been x + 4...

x - h = x + 4
-h = 4
h = -4

See the difference?

Answer 32

well... one can say the Sun is dumb by going around the sky every 24hrs
or the earth is dumb by orbiting the Sun

but math wise, is just something we wrote in notation or formula
is not like we tell the Sun or the Earth what to do according to our "dumb" rules

Answer 33

I see, so I will switch them always

Answer 34

^yep. It's just something someone observed, and made a little handy formula to use.

Answer 35

@Howard-Wolowitz yeah, I guess you can view it as "switching" them