Question

Find a unit vector tangent to the curve parametrized by x = -2t^2 - 8t + 14, y = t^3, at t=2.
I keep getting <-16,12>
but it doesn't seem to be correct.

Answer 1

<-16,12>/(sqrt(16^2+12^2))

Answer 2

It isn't asking for the magnitude though.

Answer 3

<-16,12>/(sqrt(16^2+12^2)) = <-16/(sqrt(16^2+12^2)),12/(sqrt(16^2+12^2))>

Answer 4

O.

Answer 5

My teacher failed to mention that method :(

Answer 6

"Find a unit vector"

Answer 7

Didn't cover unit vectors either.

Answer 8

Kinda rushed through this chapter due to AP exams coming up.