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(7^-2/3)^3
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use the power of a power index law and multiply the powers \[(x^a)^b = x^{a \times b}\]
(7^-2/3)^3 (1/7)^2/3 (1/7)^2 \[\sqrt[3]{1/49}\] since it is to the power of ^3 the third root cancels out going back to the answer of 1/49
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