Question

The sum of two numbers is 48 and the difference is 6. what are the numbers? @niguyver

Answer 1

x+y=48
x-y=6

Solving by elimination:
x+y=48
x-y=6
======
2x = 54
x = 27

Substituting x back in:
27-y = 6, therefore y = 21

27 and 21

Answer 2

a + b = 48
a - b = 6

solve simultaneously

just add the equations to eliminate b

Answer 3

x+y=48
x-6=y
subtract the first equation from the second.
y+6= 48-y
add y to both sides
2y+6= 48
subtract 6 from both sides
2y= 42
y= 21
x= y+6
x= 27

Answer 4

thanks guys I found the answer