Question

identify critical points then decide which critical points give local maximun and local minimun x^3-6x^2+4

Answer 1

is there diference between local max and normal max

Answer 2

@powermacho

Answer 3

Let\[y=f(x)=x^3-6x^2+4\]
Calculate \[\frac{dy}{dx}\] or \[f'(x)\]
Put\[\frac{dy}{dx}=f'(x)=0\]
Calculate the values of x for which the equation is satisfied and find the corresponding y values, these are your values of your points which are critical, the function will have a maxima or minima at these points