Question

trigonometric equation
sin^2x+cos2x-cosx=0

Answer 1

write your equation just in terms of cos(x)

Answer 2

tell me though what happens when you apply the double angle identity for cosine?
\[\cos(2x)=\cos^2(x)-\sin^2(x) \text{ by double angle identity}\]

Answer 3

I got sin^2x+(cos^2x-sin^2x)-cosx=0