Question

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line?

Answer 1

y-Y=m(x-X)
y-1=m(x-12) m=(1+3)/(12+4)=4/16=1/4
y-1=1/4(x-12)
y-1=1/4x-3
y=1/4x-2
y=mx+c standard form