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Find the vertices and foci of the hyperbola with equation (x-3)^2/16 - (y+4)^2/9= 1 Vertices: (-4, 6), (-4, 0); Foci: (-4, 0), (-4, 6) Vertices: (-4, 7), (-4, -1); Foci: (-4, -2), (-4, 8) Vertices: (6, -4), (0, -4); Foci: (0, -4), (6, -4) Vertices: (7, -4), (-1, -4); Foci: (-2, -4), (8, -4)
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