Question

I know the value of j is 16 but I don't know why it is

int i = 1;
int j = 1;
while (i < 5){
i++;
j = j * 2;
}

Answer 1

J starts as one. While i is less than five, one is added to five, and j is multiplied by two. The while statement will loop itself until the condition is met. So until I equals five, the while will run, and the value of J will constantly be multiplied by two.

Answer 2

J starts as one. While i is less than five, one is added to five, and j is multiplied by two. The while statement will loop itself until the condition is met. So until I equals five, the while will run, and the value of J will constantly be multiplied by two.

Answer 3

J starts as one. While i is less than five, one is added to five, and j is multiplied by two. The while statement will loop itself until the condition is met. So until I equals five, the while will run, and the value of J will constantly be multiplied by two.

Answer 4

I glitched Open Study, going back to the previous page will duplicate your response if you've already sent it. I don't know if I'm the only one who sees three of what I said, but it's there.

Answer 5

Im sorry I get only half of what you're saying. @adozenbabydogs

Answer 6

I understand I is 1 and j is 1 and that I will not take any more values than 5 since its less than 5 but the j is 1 that's all I understand about j

Answer 7

one times two is two, time two is four, times two is eight, times two is sixteen.

Answer 8

one times two is two, time two is four, times two is eight, times two is sixteen.

Answer 9

Im sorry I get only half of what you're saying. @adozenbabydogs

Answer 10

OK I see it's glitching I'm using my phone

Answer 11

Okay.

Answer 12

So, what don't you understand?

Answer 13

Now I get it! So there are no odd numbers involved to get the value of 16. Thanks!

Answer 14

Welcome.

Answer 15

@adozenbabydogs I got it now I'm just not properly getting the posts because I'm on my phone

Answer 16

Okay.