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16-x/3 ≥x
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|dw:1429825736802:dw|
Wow long time no see
ikr
:)
What are these problems called again?
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inequalities
Ok so we have 16- \[\frac{ x }{ 3 }\] : \[-\frac{ x-48 }{ 3 }\]
Oops
wat
nvm
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16- x/3 : - x-48/3
now you simplify
ok thanks
no no no
oh
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Im not done lol
ok
- x-48/3 \[\ge \] x
now we refine
ok
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48-x/3 \[\ge \] x
Multiply both sides by 3
x<=-16
|dw:1429826561035:dw|
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