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Mathematics 23 Online
OpenStudy (candy13106):

3x/7-3<=5+x

OpenStudy (candy13106):

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OpenStudy (anonymous):

oK what do you think you would do first?

OpenStudy (candy13106):

add 3

OpenStudy (anonymous):

Yup on the left side it would cancel out and on the right hat would you get?

OpenStudy (is3535):

3x+7=3+5x ES MUY SENCILLO. LAS ECUACIONES TIENEN DOS TERMINOS, ANTES DEL SIGNO DE IGUAL Y DESPUES. EN EL PRIMER TERMINO DEBES ACOMODAR LOS QUE TIENEN LITERAL (LETRA). SI LO CAMBIAS DEL SEGUNDO AL PRIMERO, LO PASAS CON EL SIGNO CONTRARIO. TOMARE TU EJEMPLO. 3X+7-5X=3 AHORA EN EL SEGUNDO TERMINO DEBEN QUEDAR LOS QUE NO TIENEN LITERAL. RECUERDA PASARLO CON SIGNO CONTRARIO. 3X-5X=3-7 AHORA RESUELVES. 3X-5X=-2X Y 3-7=-4 3X-5X = 3-7 -2X = -4 AHORA DEBES DEJAR SOLA A LA LETRA. VUELVES A PASAR LOS NUMEROS CON SIGNO CONTRARIO, * SI ESTA SUMANDO, PASA RESTANDO * SI ESTA RESTANDO, PASA SUMANDO * SI ESTA MULTIPLICANDO, PASA DIVIDIENDO * SI ESTA DIVIDIENDO PASA MULTIPLICANDO. COMO NO HAY SIGNO ENTRE -2 Y LA EQUIS SABEMOS QUE ESTA MULTIPLICANDO, POR LO TANTO LO PASAS DIVIDIENDO -2X = -4 X = -4/ -2 Y LO RESUELVES UTILIZANDO LEYES DE SIGNOS (- ENTRE - = MAS), 4 ENTRE DOS = 2 X = 2.

OpenStudy (candy13106):

3x/7<=8+x

OpenStudy (is3535):

so 2 is your ANSWER 2

OpenStudy (is3535):

3x+7-5x=3 -2x+7=3 -2x=3-7 -2x=--4 x=-4/(2)=2 x=2

OpenStudy (anonymous):

Yup and do you still need my help or nah?? @Candy13106

OpenStudy (candy13106):

yea

OpenStudy (anonymous):

ok. So next what do you think you would do??

OpenStudy (candy13106):

times 7

OpenStudy (anonymous):

Exactly! So it again would cancel out on the right side then on the left side you would get... ?

OpenStudy (candy13106):

3x

OpenStudy (candy13106):

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