HELP PLEASE !!!! The function S(t)=800(12)2t gives the amount of seaborgium-266, in grams, that remains in a certain sample as a function of time t, in minutes. Values of S(t) are shown in the table below. From time t=1 to t=4, what is the average decrease (in grams per minute) in the amount of seaborgium-266 present in the sample?

T(MIN) S(t)
(g.)
0 800
1 200
2 50
3 12.5
4 3.125
5 .78125
6 .1953125

Question

HELP PLEASE !!!!  The function S(t)=800(12)2t gives the amount of seaborgium-266, in grams, that remains in a certain sample as a function of time t, in minutes. Values of S(t) are shown in the table below. From time t=1 to t=4, what is the average decrease (in grams per minute) in the amount of seaborgium-266 present in the sample?

T(MIN)        S(t)
                   (g.)
0                 800
1                 200
2                  50
3                  12.5
4                  3.125
5                  .78125
6                  .1953125

misty1212 · Answer

HI!!

misty1212 · Answer

average just means the slope
the slope of the line through $(4,3.125)$ and $(1,200)$