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Mathematics 20 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

Are you sure that's what the question says?

OpenStudy (anonymous):

Maybe she meant "has a length of 5b-6 and a width of 3b-1?" Do you want to try that?

OpenStudy (anonymous):

Okay well if that's it. What equation do you use to find the area of a rectangle?

OpenStudy (anonymous):

There you go. So if you want to find the area of the frame, which is a rectangle you would multiply your length *width. Remember your finding the area of the frame, so it would be (5b-1) (3b-1)

OpenStudy (anonymous):

There you go, I was just about to tell you that!

OpenStudy (anonymous):

Correct

OpenStudy (anonymous):

(15b^2-23b+6)-(3b^2+15b)

OpenStudy (anonymous):

GREAT! Keep going you're almost done!

OpenStudy (anonymous):

Almost. The middle term, is wrong. It's -23b+15b, so you would get -8.

OpenStudy (anonymous):

-8b***

OpenStudy (anonymous):

So 12b^2-8b+6, it's okay.

OpenStudy (anonymous):

Do you have anything else to go with the question? What math are you in? What are you currently learning?

OpenStudy (anonymous):

Then yes, that should be your answer if I'm not mistaken.

OpenStudy (anonymous):

You're welcome!

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