A charity fair raised $6,000 by selling 500 lottery tickets. There were two types of lottery tickets: A tickets cost $10 each, and B tickets cost $60 each. How many tickets of each type were sold?
We have to set up a system of equations. So the total amount of tickets sold was 500. So A + B = 500. The total amount of money made was 6000. 10a + 60b = 6000 So our system is A + b = 50 10a + 60b = 6000
ok... but what would be the next step im confused by math
There are multiple ways to solve a system of equations. Let's use the elimination method. We want to eliminate a variable by combining the equations. But first, we need to make that possible. Let's work to eliminate the a variable. What can we do to the first equation to make it so the a It's eliminated when we combine?
Is* not it's, sorry. I'm on a tablet
its ok but i started plugging in answer choices with the formula and i got 10(480) + 60(20) = 4800 + 1200 = 6000
so its 480 and 20
Well I guess that's one way to get your answer lol. Do you still wanna work it out with me, though? So you know what to do on other problems?
no its fine but thanks
Alrighty. Best of luck~
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