May I get some help with the second part of this problem? http://assets.openstudy.com/updates/attachments/553af898e4b0cdd5b3a7fb88-withheldtao2-1429930350326-screenshot3.png

Question

May I get some help with the second part of this problem?  http://assets.openstudy.com/updates/attachments/553af898e4b0cdd5b3a7fb88-withheldtao2-1429930350326-screenshot3.png

matlee · Answer

A

anonymous · Answer

A?

amistre64 · Answer

what do you need help on?  you have the data, and the rest is just adding

amistre64 · Answer

the error estimate eh ...

anonymous · Answer

Yeah... The error estimate.

amistre64 · Answer

can you walk me thru what you error estimation process is?  id have to refresh my memory on it anyways.

anonymous · Answer

I know that the preview is off, the 4 needs to be squared.

amistre64 · Answer

http://math.cmu.edu/~mittal/Recitation_notes.pdf

anonymous · Answer

Give me a second to read.

amistre64 · Answer

given:$$|f''(x)|\le K~:~k\in R$$
$$|E_m|\le \frac{k(b-a)^3}{24n^2}$$

amistre64 · Answer

if 

-4 <= f''(x)  <= 1

then |f''(x)| <= 4  right?

amistre64 · Answer

filling in we get:
$$|E_m|\le \frac{4(3.2-0)^3}{24(4)^2}$$
$$|E_m|\le \frac{(3.2)^3}{24(4)}$$

anonymous · Answer

Yes. That was it. Thank you!

amistre64 · Answer

i cant tell you why thats the error, its just a formula i found on the google lol.  glad it works tho