What is the integral of this function?
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Let f be an odd function, that is f(-x)=-f(x) . We know that integral 0^5 f(x)=3. Then using properties of definite integrals we conclude that
integral -5^5 f(x)= -3
integral -5^5 f(x)= 0
integral -5^5 f(x)= 2
integral -5^5 f(x)= 3
I'm confused on how to set it up from the integral range they are giving how would this affect the answer?
Suppose a function f(t) satisﬁes
(integral of 1 to 4/3) f(t) dt = 1/2
(integral of 4/3 to 64) f(t) dt = 7
Compute the integral
(integral from 1 to 1+
Laplace transform of a function f(x) is function (Lf)(s) of the variable s defined by the improper integral
Why is the integral of an odd function from -A to A equal to zero?
The definition of an odd function is f(-x)=-f(x)
Taking the Integral from -A to A, we s
Write the integral as the sum of the integral of an even and odd function to evaluate the integral.
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Can someone help me with this integral question?
You are given the four points in the plane
A = (7,-7),
B = (11,8),
C = (13,-6),
D = (16,3).
What is the next step for this construction
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