The profit of a company in thousands of dollars is given by the quadratic function P(x) = 3000 + 1200x - 6x2 where x is the amount, in thousands, the company spends on advertising. Find the amount, x, that the company has to spend to maximize its profit.
A) 100 B) 1,000 C) 10,000 D) 100,000
PLEASE HELP ME WITH THIS PROBLEM IT'S CONFUSING MEE
@Mehek14
@amistre64
@GBMK92
@yajna
@welshfella
@~Gelmhar
you need to find the maximum value of P(x) - well the value of x that gives this maximum value
@tywower - at what stage are you in mathematices. Have you done any calculas ?
it's been a while
differentiation?
idk
Ok we can do this by cnoverting the quadratic to vertex form
okay because I'm practicing problems for an upcoming test and need to know how to do this again to actually pass the exam
gotta go - be back in 5 minutes
What type of math is this?
we can rewrite the equation as -6x2+1200x+3000 and then we divide by -6 which = to x2-200x-500 then we solve by using this equation |dw:1429981312221:dw|
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