The profit of a company in thousands of dollars is given by the quadratic function P(x) = 3000 + 1200x - 6x2 where x is the amount, in thousands, the company spends on advertising. Find the amount, x, that the company has to spend to maximize its profit.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (tywower):
A)
100
B)
1,000
C)
10,000
D)
100,000
OpenStudy (tywower):
PLEASE HELP ME WITH THIS PROBLEM IT'S CONFUSING MEE
OpenStudy (tywower):
@Mehek14
OpenStudy (tywower):
@amistre64
OpenStudy (tywower):
@GBMK92
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (tywower):
@yajna
OpenStudy (tywower):
@welshfella
OpenStudy (tywower):
@~Gelmhar
OpenStudy (welshfella):
you need to find the maximum value of P(x) - well the value of x that gives this maximum value
OpenStudy (welshfella):
@tywower - at what stage are you in mathematices. Have you done any calculas ?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (tywower):
it's been a while
OpenStudy (welshfella):
differentiation?
OpenStudy (tywower):
idk
OpenStudy (welshfella):
Ok we can do this by cnoverting the quadratic to vertex form
OpenStudy (tywower):
okay because I'm practicing problems for an upcoming test and need to know how to do this again to actually pass the exam
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (welshfella):
gotta go - be back in 5 minutes
OpenStudy (anonymous):
What type of math is this?
OpenStudy (anonymous):
we can rewrite the equation as -6x2+1200x+3000
and then we divide by -6 which = to x2-200x-500
then we solve by using this equation |dw:1429981312221:dw|