Question

Find the range of the function

Answer 1

@Michele_Laino @rational @inowalst @jagr2713 @jigglypuff314 @misty1212 @quickstudent @Preetha

Answer 2

hint:
we have to solve your integral

Answer 3

in order to that, the subsequent substitution, can be useful:
\[t = 4\sin \theta \]
where \theta is the new variable of integration

Answer 4

\[\int\limits \sqrt{a^2-x^2}=?\]

Answer 5

\[x/2\sqrt{a^2-x^2}+a^2/2 \sin^{-1} (x/a)\]

Answer 6

right? @Michele_Laino

Answer 7

that's right! @rvc