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GIVING MEDALS f and f^-1 are functions. if f(2)=pi+7, then f^-1(pi+7)=?
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@Preetha @nincompoop
\[f*f^{-1}=1\]
multip-ly both side by f^{-1}
can u do it @em2000
i dont know how
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\[f^{-1} *f(2)=f^{-1}(\pi+7)\]
\[f^{-1}*f=1\]
on left side we will left with only 2
so \[f^{-1} (\pi+7)=???\]
@em2000
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10.14??
on left side f inverse and f will cancel each other so we left with 2 only
OMG I GET IT
THANK U SO MUCH SORRY IT JUST TOO A WHLE @gorv
you r welcome :)
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