Maria will spin the arrow on the spinner 3 times. What is the probability that the arrow will stop on A, then B, then C? A. 3/256 B. 1/64 C. 1/12 D. 3/4
Find the probability of landing on A. Find the prob of landing on B. Find the prob of landing on C. Multiply all three probabilities together.
I am assuming this is drawn to scale?
the probabilities are multiplied because each spin is independent of the previous one
so how would i multiply them?
Just multiply them together. But first find the probability of landing on A, B, and C.
3 times A b c ?
@dan815
@Preetha
P(A)=1/4 P(B)=1/4 P(C)=1/4 In cases where the steps of experiments are independent (i.e. one outcome does not affect the others), you would multiply the probabilities, i.e. P(ABC)=P(A)*P(B)*P(C) Multiplying by 3 is equivalent to adding them together which does not give the correct answer in this case.
so im going to multiply 1/4? @mathmate
Tell me how you do that, please.
well you put P(ABC)=P(A)*P(B)*P(C) So i was thinking 1/4*1/4*1/4 lol sorry i dont know how to do probability
That sounds promising. What do you get?
0.25
Can you put 1/4*1/4*1/4 on a calculator? I get a different number, perhaps I have made a mistake.
Yes on google
that's ok too!
What do you get?
when i multiply them? 0.25..
did you put 1/4*1/4*1/4 into google?
Yes
and you got 0.25?
yes
Did you put in 1/4*1/4*1/4 ?
Yes
do you know the answer?
I get a totally different answer, much smaller than 0.25. Are you sure you put in all the numbers in 1/4*1/4*1/4, i.e. 3 ones, 3 fours, separated by * and / exactly as shown?
ahhhhh lol now im getting a diff answer also 0.015625
1/64
That is correct! It took a little while, but it's worth the work and time! congrats.
Thank You!
You're welcome! :)
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