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If x = Arc sin (-1/2), find angle x.
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Sketch a right triangle, angle A at the left. since cos A = 1/x, label the side adjacent to A with 1, hypotenuse with x. So side opposite A must be √(x² - 1). A = arc cos 1/x, thus sin A = sin(arc cos 1/x) = [√(x² - 1)]/x
So in other words it's sin inverse (-1/2)?
YES
thanks buddy
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