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Iron-59 has a half-life of 45.1 days. How old is an iron nail if the Fe-59 content is 25% that of a new sample of iron
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For count to reduce to 25%, 2 half-lives would have passed since 1/4 = (1/2)^2. So what do you think is the answer?
25=100 e^(-.693 t/45.1) take the ln of each side... Ln(25)=ln(100) -.693 t/45.1 ln(25)-ln(100)=-.693 t/45.1 ln(25/100)=-.693t/45.1 t= - 45.1/.693 ( ln .25) t = 65
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