An adventure game has a number cube with 12 equal-size faces: some labeled with 1, some labeled with 2, and some labeled with 3. The game manufacturer tests the cube by rolling it 12, then 120, and then 1200 times.
What is the best estimate of the number of faces labeled with 2?
Outcome Number of trials
12 120 1200
1 5 67 617
2 6 48 394
3 1 25 189
A.
1
B.
2
C.
4
D.
6
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OpenStudy (anonymous):
hlp
OpenStudy (anonymous):
@dan815
OpenStudy (anonymous):
b? idk
OpenStudy (anonymous):
@mathsciencehistory
OpenStudy (anonymous):
@Cblount
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OpenStudy (anonymous):
@youngortiz13
OpenStudy (anonymous):
b
OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
medal plesase
OpenStudy (anonymous):
how do i do that i new kinda
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OpenStudy (anonymous):
haha report...
OpenStudy (anonymous):
no direct answers u know that right
OpenStudy (anonymous):
no im verry confused
OpenStudy (anonymous):
@bohotness @confluxepic @EclipsedStar maybe they cant help u
OpenStudy (anonymous):
oh thanks
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OpenStudy (anonymous):
@jigglypuff314
OpenStudy (anonymous):
@bohotness
OpenStudy (anonymous):
@confluxepic
OpenStudy (anonymous):
i have 3 more questions left
OpenStudy (anonymous):
@EclipsedStar
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jigglypuff314 (jigglypuff314):
Do you need help with this question?
B is incorrect
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
openstudy is dying id say sleepy do you think openstudy is dying
jigglypuff314 (jigglypuff314):
alright ^_^
for experimental probability, probability becomes more accurate with more tries
so the 1200 trials would be the most accurate
so let's use the information from that
about what percent chance based on that column is there to role a 2?
OpenStudy (anonymous):
qualified helper lol that means you can ban people?
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OpenStudy (anonymous):
i gtg ttyl
OpenStudy (anonymous):
:( still confused
jigglypuff314 (jigglypuff314):
394 out of 1200
what percent chance is that?
OpenStudy (anonymous):
idk but do you divide
jigglypuff314 (jigglypuff314):
yes :)
394 divided by 1200
what would you get?
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OpenStudy (anonymous):
0.3 and a bunch of other numbers
jigglypuff314 (jigglypuff314):
yes :)
then multiply that number by 12 (the number of sides)
jigglypuff314 (jigglypuff314):
then round to the nearest whole number
OpenStudy (anonymous):
3.94
OpenStudy (anonymous):
then round?
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